Calculating the profile for plasterboard: features baffle device doorway frame count, opening and racks
Table of contents
1 The calculation for the partition with the door opening
- 1.1 Frame
- 1.2 aperture
- 1.3 Stands
- 2 We go to shop
- 3 conclusion
How to start building? Right! From calculations and estimates. Even when it comes to such a simple construction as drywall. So today we will analyze the question of how to calculate a profile for drywall.
For convenience it is better to use a drawing or diagram.
The calculation for the partition with the door opening
In the photo the general form of construction
In Example partitions for room height of 3 m and 5 m wide, we show how to calculate the number of profiles for plasterboard. So, as you can see in the photo, the doorway is located at a distance of 1 m from the wall to the right, has a height of 210 cm and a width of 80 cm.
Broad line indicates the frame, which is attached to the wall and consists of UD-profile. The perimeter of this frame is 5 × 2 + 3 × 2-0,8 m = 15.2 m is rounded and obtain 16 m 3 If we use the meter slats obtain.. 16/3 = 5 (3). We are rounded and get 6 pieces of UD-strips on the frame. (Cm. also the article Profile for plasterboard: features).
On our site you can find an online calculator to calculate the amount of material, including a plaster.
That's the theory. Now let's look at the practical side.
Instructions on the calculation based on cutting out:
- On the wall we go 2 slats entirely without trimmingSince the height of the room is equal to the length of the profile - 3 m.
- On the ceiling is placed 1 whole rack 1 and clipped -. 3 + 2 = 5 m remains residue of 1 m length.
- If we look at the floor, we'll see where this goes the rest of: Between the wall on the left and the opening-meter span.
- Next we have the doorwayBehind which it remains 5-1-0,8 = 3.2 m. This whole rack 1 and another piece of 20 cm long.
- Total on frame requires five strips UD whole length of 3 m and 20 cm long piece.
Yes, sometimes for the sake of the balance you have to buy a size, but we will see more - maybe we'll get lucky, and somewhere will remain a scrap?
Any complex shape can be divided into separate elements and calculate
So, following the logic of rack mounting, proceed to the next item - opening. As already mentioned, this element should be enhanced using binary systems - are inserted into each other CW and CD bracket.
Here is what we see, that the calculation of the number of profiles for plasterboard in practice may differ from the elegant formula derived theoretically.
On the sides we will install 2 double rail. This means we will need: 2 CD and 2 CW profile, each 3 m long jumper will be made from CD-rack, and it adds another standard size.. (Cm. also the article Decorating the living room with plasterboard: features).
Do not forget about the reinforcement of the door opening frame, otherwise your walls will shake at every door movement.
After mounting webs remain 3-0,8 = 2,2 m form CD rack. But we remember that above the horizontal jumper put 2 more vertical, as in the photo:
Typically, the horizontal top web is connected with two vertical roof rack
The length of each vertical jumper is 3-2,1 = 0,9 m Two such bridges will require length of 1.8 m, and the rest of us -. 2.2 m, we have invested and buy another standard size is not necessary.
On opening, it took us 2 and CW 3 CD rack. The residue 2,2-1,8 m = 0,4 CD-rack. It is a pity that not UD, remember, we do not have 20 cm? Moving on.
To understand how to calculate the user's profile under the drywall, you must know the order of the frame assembly. Our thoughts are the way to be doing this in steps. After mounting the opening proceed to the uprights. In the photograph, we indicate which design elements are called rack-mount, and which guides.
We know that the rack elements are mounted in steps of 60 cm. The door smashed the wall into two parts: 1 m to 3.2 m on the left and on the right (see the figure at the beginning of the article).
The width of the sheet is 1.2 m GCR means that meter span overlaps completely. The vertical jumper over the door is placed at a distance of 20 cm from the lateral strut for joining sheet GCR.
It is obvious that on this interval we put 1 rack in the middle, at a distance of 50 cm from the wall. Move on.
On the other hand we have a 3.2 m partitions. 3,2/0,6=5(3). Five racks and 20 cm in the residue. Cover the 20-inch span need not.
So, we need as many as 6 of rack bars, which leave no residue.
We go to shop
For high structures may require horizontal bridges for joining sheets
To sum up: if you decide to build a partition with his hands, but did not know how to make a calculation of the profile under the drywall, you should not blindly trust an online calculator. These programs are not accurate and does not take into account the nuances of the nuances and will depend not only on the price of the event, but also the construction period.
Having considered the detailed calculation, we have received:
- The frame will require 6 UD-bars.
- At the doorway leave CW 2 and 3 CD rack.
- On reception requires 6 CW profiles.
It is worth studying the tables to facilitate calculation of consumable items. We also recommend watching the video, which describes how to better and more convenient to consider the amount of material required. To calculate the best to have a drawing, it will still need to work.