Determine the weight of the reinforcement - the table by the cross-section of the rod and the order of calculations

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Armature Concrete or cement-sand mixtures are used in almost all types of work related to the field of restoration, construction or repair. As a rule, any "pouring" into the mold is made after the preliminary installation( laying) of the reinforcement structure. Most often it is built of metal rod.

Why you need to know the weight of the

  • fittings When adjusting ceilings or elements that have supports - to determine the maximum additional load that the bar will create. This will help determine the appropriateness of using it or the need to replace it with an analog( metal or plastic grid).
  • For correct evaluation of reinforcement quality( metal content in concrete).
  • To select the mode of transport when transporting material to the place of use.
  • For the preparation of preliminary estimates of works at the design stage and finding ways of reasonable savings.

In the private sector, rods with diameters from 6 to 16 mm are used. Thicker samples are already a sphere of industrial use. All the necessary data are listed in the table.

Conductor cross-section( mm)
6 8 10 12 14 16
Weight 1 lm( kg) 0, 22 0,39 0,62 0,89 1,21 1,58

It should be understood that the figures given are only approximate, but quite sufficient for preliminary calculations. They do not take into account the steel grade( rod class).But such nuances are necessary for designers, and they have special calculation tables. In addition, the weight is theoretical and actual. The difference in values ​​can range from a fraction of 3%.

If you do not have a PC or reference literature at hand, you can determine the approximate weight of all the rods using a conventional roulette and pencil. It is done this way:

 The specific weight of the material( steel) is taken to be 7 850 kg / m³.It remains to determine the volume. If the cross-section of the bars is not known, then the measurement is made. The same is with respect to their length. And then, as taught in school - the volume is equal to the cross-sectional area.
  • D( or R2) is multiplied by 3.14( constant value) and the total length of all samples.
  • Total mass of material =( volume) x( specific gravity).

As you can see, nothing is complicated in the calculations. Of course, this applies only to metal fittings, not composite.

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